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  1. import re
  2.  
  3. regex = r"^BEGIN\b.*(?:\r?\n(?!(?:BEGIN|END)\b).*)*\r?\nEND"
  4.  
  5. test_str = ("Some_text Some_text 1 2 3\n"
  6. 	"BEGIN Some_text Some_text\n"
  7. 	"44 76 1321\n"
  8. 	"Some_text Some_text\n"
  9. 	"END Some_text\n"
  10. 	"Some_Text Some_text 1 4 5\n")
  11.  
  12. print(re.findall(regex, test_str, re.MULTILINE))
Success #stdin #stdout 0.02s 9464KB
comments (?)
stdin 
Standard input is empty
stdout 
['BEGIN Some_text Some_text\n44 76 1321\nSome_text Some_text\nEND']
https://ideone.com/AgGBd0
language:
Python 3 (python  3.9.5)
created:
4 years ago
visibility:
secret

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