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  1. import re
  2. s = "Employee ID DF856, Year 2016, Department Finance, Team 2, Location 112 20161 12016 120162"
  3. print(re.findall(r'(?<!\d)(?!2016(?!\d))\d{3,}', s))
  4.  
  5. print([x for x in re.findall(r'\d{3,}', s) if x != "2016"])
  6.  
Success #stdin #stdout 0.02s 27712KB
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Standard input is empty
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['856', '112', '20161', '12016', '120162']
['856', '112', '20161', '12016', '120162']
https://ideone.com/ALMm99
language:
Python 3 (python  3.9.5)
created:
6 years ago
visibility:
public

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