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  1. #include <stdio.h>
  2.  
  3. float polyn(float a[], int n, float x) {
  4. 	float acc = a[n - 1];
  5. 	for (int i = n - 1; i >= 1; i--)
  6. 		acc = acc * x + a[n - 1];
  7. 	return acc;
  8. }
  9.  
  10. int main(void) {
  11. 	float coeffs[] = { 1, 1, 1, 1, 1, 1, 1, 1, 1 };
  12. 	printf("%f\n", polyn(coeffs, 9, 1));
  13. 	printf("%f\n", polyn(coeffs, 9, 2));
  14. 	printf("%f\n", polyn(coeffs, 9, 3));
  15. 	return 0;
  16. }
  17.  
Success #stdin #stdout 0s 5320KB
comments (?)
stdin 
Standard input is empty
stdout 
9.000000
511.000000
9841.000000
https://ideone.com/9yUqwm
A fast procedure for evaluating a polynomial, using the Horner's method
language:
C (gcc 8.3)
created:
15 days ago
visibility:
public

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