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  1. import re
  2. s='2223334441214844'
  3. print([x.group() for x in re.finditer(r'(\d)\1*', s)])
Success #stdin #stdout 0.02s 6884KB
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Standard input is empty
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['222', '333', '444', '1', '2', '1', '4', '8', '44']
https://ideone.com/8eb7hG
language:
Python (cpython 2.7.16)
created:
6 years ago
visibility:
public

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