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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4. 	int a[3] = {1,2,3};
  5.  
  6. 	int *p = a ;
  7.  
  8. 	for(int i=0; i<3; i++){
  9. 		printf("a[%d]のアドレス ：%p \n", i, a+i);
  10. 		printf("ポインタ演算p+%d：%p \n", i, p+i);
  11. 	}
  12. 	return 0;
  13. }
  14.  
Success #stdin #stdout 0s 5288KB
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stdin
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Standard input is empty
stdout
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a[0]のアドレス ：0x7fffd014529c 
ポインタ演算p+0：0x7fffd014529c 
a[1]のアドレス ：0x7fffd01452a0 
ポインタ演算p+1：0x7fffd01452a0 
a[2]のアドレス ：0x7fffd01452a4 
ポインタ演算p+2：0x7fffd01452a4
https://ideone.com/8ObZ2Y
language:
C (gcc 8.3)
created:
28 days ago
visibility:
public

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