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  1. #include <stdio.h>
  2. #define N 5 // степень
  3. #define M 5 // размер числа
  4.  
  5. void multiply(int* in1, int* in2) {
  6.     int cr;
  7.     int tmp[N + 5];
  8.     for (int i = 0; i <= in2[0]; i++)
  9.         tmp[i] = in2[i];
  10.  
  11.     in2[0] = 0; // будем считать что переменная чистая    
  12.     for (int i = 1; i <= in1[0]; i++) 
  13.         for (int j = 1; j <= tmp[0]; j++) {
  14.             cr = in1[i] * tmp[j];
  15.             for(int k = i + j - 1; cr > 0; k++) {
  16.                 if (k > in2[0])
  17.                     in2[0] = k;
  18.                 else
  19.                     cr += in2[k];
  20.                 in2[k] = cr % 10;
  21.                 cr /= 10;
  22.             }
  23.      }
  24. }
  25. void writelong(int* y){
  26.     for (int i = y[0]; i > 0; i--)
  27. 		printf("%d",y[i]);
  28. }
  29.  
  30. int main(void) {
  31. 	int n;
  32.     int y[N*M];
  33.     int out[N*M];
  34.  
  35. /*  int a[N]; */
  36.     int a[] = {2,5,1}; /* First number 15 */
  37.     n = M;             /* Degree of number  5*/
  38.  
  39.     for (int i = 1; i < N * M; i++)
  40. 		out[i] = 0;
  41.  
  42. /*  printf("Enter the first number ");
  43.     readlong(a); 
  44.     printf("\nEnter the stepen "); 
  45.     scanf _s("%d", &n);*/
  46.     y[0] = y[1] = 1;    
  47.     for (int i = 0; i < n; i++) 
  48.         multiply(a,y);
  49.     writelong(a);
  50.     printf("^%d=",M);
  51.     writelong(y);
  52. 	return 0;
  53. }
Success #stdin #stdout 0s 4164KB
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stdin
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Standard input is empty
stdout
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15^5=759375
https://ideone.com/7BY4cb
language:
C (gcc 8.3)
created:
6 years ago
visibility:
public

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