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  1. #include <iostream>
  2. #include <stdlib.h>
  3. #include <math.h>
  4. #include <string.h>
  5.  
  6.  
  7. using namespace std;
  8.  
  9. char* stringMerge(char* str1,char *str2)
  10. {
  11.    int dlstr1 = 0, dlstr2 = 0, dlnowy = 0;
  12.  
  13.    dlstr1 = strlen(str1);
  14.    dlstr2 = strlen(str2);
  15.  
  16.    if (dlstr1 <= dlstr2)
  17.         dlnowy = dlstr1;
  18.    else dlnowy = dlstr2;
  19.  
  20.     char *nowyString ;
  21.  
  22.     dlnowy = 2*dlnowy;
  23.     nowyString = new char [dlnowy+1];
  24.  
  25.     //cout << "dlugosc: "<<dlnowy<< endl;
  26.  
  27.     int i=0,j=0;
  28.  
  29.     do
  30.     {
  31.         nowyString[i] = str1[j];
  32.         i++;
  33.         j++;
  34.         nowyString[i] = str2[j-1];
  35.         i++;
  36.     }while(i<dlnowy);
  37.  
  38.     //nowyString[dlnowy] = '/0';
  39.  
  40.    // cout << "ostatni "<<nowyString[dlnowy] << endl;
  41.  
  42.     return nowyString;
  43. }
  44.  
  45.  
  46. string napis1, napis2;
  47.  
  48. int main()
  49. {
  50.     char *nowySTR;
  51.     int ilosc_testow;
  52.     string *tabwynikow;
  53.  
  54.    // cout << "podaj ilosc testow : "<< endl;
  55.     cin>>ilosc_testow;
  56.  
  57.     tabwynikow = new string[ilosc_testow];
  58.  
  59.     for(int i=0; i<ilosc_testow;i++)
  60.     {
  61.        //cout << "podaj stringi "<< endl;
  62.        cin>>napis1>>napis2;
  63.        nowySTR = stringMerge(&napis1[0], &napis2[0]);
  64.  
  65.        tabwynikow[i] = nowySTR;
  66.       // delete [] nowySTR;
  67.     }
  68.  
  69.     for(int i=0;i<ilosc_testow;i++)
  70.     {
  71.         cout<<tabwynikow[i]<<endl;
  72.     }
  73.  
  74.  
  75.     delete [] tabwynikow;
  76.     return 0;
  77. }
  78.  
Success #stdin #stdout 0.04s 4420KB
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https://ideone.com/6gRVyb
problem PP0504B, based on SPOJ submission 22200950 (CPP), 2018-08-22 22:01:09
language:
C++ (gcc 8.3)
created:
5 years ago
visibility:
secret

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