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  1. def repeatedString(s, n):
  2.   dm = divmod(n, len(s))
  3.   c1 = s.count("a") * dm[0]
  4.   c2 = s[:dm[1]].count("a")
  5.   return c1 + c2
  6.  
  7. print(repeatedString('abc',11234567890987654321))
Success #stdin #stdout 0.02s 9172KB
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3744855963662551441
https://ideone.com/6bugVL
language:
Python 3 (python  3.12)
created:
4 years ago
visibility:
public

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