# by noordean
x=0
for n in range(2,30000):
for i in range(2,n/2):
if n%i==0:
break
else:
x+=1
if x==3000: #3000th term
print n
IyBieSBub29yZGVhbgp4PTAKZm9yIG4gaW4gcmFuZ2UoMiwzMDAwMCk6CiBmb3IgaSBpbiByYW5nZSgyLG4vMik6CiAgaWYgbiVpPT0wOgogICBicmVhawogZWxzZToKICB4Kz0xCiAgaWYgeD09MzAwMDogIzMwMDB0aCB0ZXJtCiAgIHByaW50IG4=