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  1. import re
  2.  
  3. pattern = r"^/home/user(?:/[^/\n]+)+"
  4.  
  5. s = ("/home/user\n"
  6. 	"/home/user/\n"
  7. 	"/home/user/foo\n"
  8. 	"/home/user/bar/foo")
  9.  
  10. print(re.findall(pattern, s, re.M))
Success #stdin #stdout 0.03s 9712KB
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stdin
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Standard input is empty
stdout
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['/home/user/foo', '/home/user/bar/foo']
https://ideone.com/61wzew
language:
Python 3 (python  3.12)
created:
1 year ago
visibility:
secret

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