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  1. # include <stdio.h>
  2.  
  3. int isPalindrome(char s[]){
  4. 	int i, length = 0;
  5.  
  6.     while(s[length] != '\0')
  7.     	length++;
  8.  
  9.     for (i = 0; i < length / 2; i++) {
  10.         if (s[i] != s[length - 1 - i]) {
  11.             return 0;
  12.         }
  13.     }
  14.  
  15.     return 1;
  16. }
  17.  
  18. //メイン関数は書き換えなくてよいです
  19. int main(){
  20.     char s[100];
  21.     scanf("%s",s);
  22.     printf("%s -> %d\n",s,isPalindrome(s));
  23.     return 0;
  24. }
  25.  
Success #stdin #stdout 0s 5316KB
comments (?)
stdin
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durgru
stdout
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durgru -> 0
https://ideone.com/5SyNc1
課題3
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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