#цикл бір код бөлігін бірнеше рет немесе бір шартқа сәйкес қайталау
#for
#1 ден 10ға дейін барлық сандарды шағару
for i in range(1, 11):
print(i, end=' ')
print('\n')
#әрбір символдың сонына ! қою
for c in 'abcde213':
print(c + '!', end="")
#while шартты цикл
#248 саны 2ге қанша рет бөлінетінін анықтау
print('\n')
counter = 0
n = 248
while n % 2 == 0:
n //= 2 # n = n // 2
counter += 1
print(counter)
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