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  1. from collections import Counter
  2.  
  3.  
  4. def contacodon(seq):
  5.     stops = ["TAA", "TAG", "TGA"]
  6.     count = Counter()
  7.     for i in range(seq.find('ATG'), len(seq) + 1, 3):
  8.         codon = seq[i: i + 3]
  9.         count.update([codon])
  10.         if codon in stops:
  11.             break
  12.     return dict(count)
  13.  
  14.  
  15. seq = "GCGATCGAGATGAGCATCGCATCGCGGACTACCGCGCGCGCGCGCGGGAGATGAGCATCGACGACTCGACTAG"
  16. print(contacodon(seq))
  17.  
Success #stdin #stdout 0.04s 9092KB
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{'ATG': 1, 'AGC': 1, 'ATC': 1, 'GCA': 1, 'TCG': 1, 'CGG': 1, 'ACT': 1, 'ACC': 1, 'GCG': 2, 'CGC': 2, 'GGG': 1, 'AGA': 1, 'TGA': 1}
https://ideone.com/3sguVJ
https://pt.stackoverflow.com/q/513466/69296
language:
Python 3 (python  3.9.5)
created:
2 years ago
visibility:
secret

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