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  1. import re
  2.  
  3. regex = r"^(\d{1,3}\.?(?:\d{1,3}\.?)*)? ?([^\W\d]+)"
  4.  
  5. s = ("section\n"
  6. 	"1 section\n"
  7. 	"2. section\n"
  8. 	"2.1 subsection\n"
  9. 	"2.1.1 subsection\n"
  10. 	"2.1.1. subsection")
  11.  
  12. print(re.findall(regex, s, re.MULTILINE))
Success #stdin #stdout 0.03s 9560KB
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stdin
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Standard input is empty
stdout
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[('', 'section'), ('1', 'section'), ('2.', 'section'), ('2.1', 'subsection'), ('2.1.1', 'subsection'), ('2.1.1.', 'subsection')]
https://ideone.com/3orAYa
language:
Python 3 (python  3.12)
created:
4 years ago
visibility:
public

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