meany = ... @(n)1+sum(fix(log2(1:n-1)))/n meany(1) meany(2) meany(3) meany(4) meany(5) meany(6) meany(7)
Standard input is empty
meany = @(n) 1 + sum (fix (log2 (1:n - 1))) / n ans = 1 ans = 1 ans = 1.3333 ans = 1.5000 ans = 1.8000 ans = 2 ans = 2.1429