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  1. using System;
  2. using System.Text.RegularExpressions;
  3.  
  4. public class Test
  5. {
  6. 	public static void Main()
  7. 	{
  8. 		var data = new string[] {"trabc@abtrec.com.lo", "demomail@demodomain.com"};
  9. 		foreach (var s in data) {
  10. 			var res = Regex.Replace(
  11. 				s
  12. 			,   @"^.*(?=.{2}\@.{2})|(?<=.{2}\@.{2}).*(?=.com.*$)"
  13. 			,   match => new string('*', match.ToString().Length)
  14. 			);
  15. 			Console.WriteLine("'{0}' ---> '{1}'", s, res);
  16. 		}
  17. 	}
  18. }
Success #stdin #stdout 0.07s 19476KB
comments (?)
stdin
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Standard input is empty
stdout
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'trabc@abtrec.com.lo' ---> '***bc@ab****.com.lo'
'demomail@demodomain.com' ---> '******il@de********.com'
https://ideone.com/3X5J9T
language:
C# (gmcs 5.20.1)
created:
7 years ago
visibility:
public

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