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  1. def part3(n):
  2.     for sh in range(1, (n-2)//2+1):
  3.         for mid in range(sh+1, (n-sh) // 2 + 1):
  4.             la = n - sh - mid
  5.             print(sh, mid, la)
  6.  
  7. part3(10)
  8.  
Success #stdin #stdout 0.03s 9276KB
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stdin
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Standard input is empty
stdout
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1 2 7
1 3 6
1 4 5
2 3 5
2 4 4
https://ideone.com/2kPL60
language:
Python 3 (python  3.9.5)
created:
2 years ago
visibility:
public

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