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  1. #include <stdio.h>
  2. #include <math.h>
  3.  
  4. int main(void) {
  5.     int cnt = 0;
  6.     int n;
  7.  
  8.     for( n = 1; n <= 21; n++ ) {
  9.         cnt += 10 - ceil(pow(10, 1 - (1.0 / (double)n)));
  10.     }
  11.  
  12.     printf("%d\n", cnt);
  13.  
  14.     return 0;
  15. }
  16.  
Success #stdin #stdout 0s 2168KB
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49
https://ideone.com/25WkBn
language:
C (gcc 8.3)
created:
7 years ago
visibility:
public

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