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  1. #include <iostream>
  2. using namespace std;
  3. int main()
  4. {
  5. 	string haslo, haslo1;
  6. 	bool ok = true;
  7. 	int n;
  8. 	cin >> n;
  9. 	for(int i = 0; i < n; i ++){
  10. 		cin >> haslo >> haslo1;
  11. 		for(int x = 0; x < haslo.length(); x++){
  12. 			if(haslo.length() != haslo1.length()){
  13. 				ok = false;
  14. 				break;
  15. 			}
  16. 			else if(haslo[x] != haslo1[x]){
  17. 				if(haslo1[x] != '*')
  18. 					ok = false;
  19. 					break;
  20. 			}
  21. 		}
  22. 		if(ok)
  23. 			cout << "ok" << endl;
  24. 		else
  25. 			cout << "error" << endl;
  26. 	}
  27.  
  28. }
Success #stdin #stdout 0s 4524KB
comments (?)
stdin
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2
fraktal
**ak**l
FRAKTAL
F*RAKTAL
stdout
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ok
error
https://ideone.com/1THzIB
language:
C++ (gcc 8.3)
created:
3 years ago
visibility:
public

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