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  1. #include <stdio.h>
  2. int main(void) {
  3. 	int n=0;
  4. 	int sum=0;
  5. 	scanf("%d",&n);
  6. 	while( n <= 100 )
  7. 	{
  8. 		if((n%3!=0)&&(n%5!=0)&&(n%10>=6)&&(n>=6))
  9.     sum =sum + n;
  10.     n = n + 1;
  11. 	}
  12. 	printf("3の倍数でもなく5の倍数でもない数字の合計は%dです。 \n",sum);
  13. 	return 0;
  14. }
  15.  
Success #stdin #stdout 0.01s 5292KB
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3の倍数でもなく5の倍数でもない数字の合計は1365です。
https://ideone.com/14v6RN
language:
C (gcc 8.3)
created:
9 days ago
visibility:
public

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