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  1. #include <stdio.h>
  2.  
  3. void cal(int x, int y, int *sum, int *diff, int *mul, int *mod){
  4. 	*sum=x+y;
  5. 	if(x>y){
  6. 		*diff=x-y;
  7. 	}
  8. 	else{
  9. 		*diff=y-x;
  10. 	}
  11. 	*mul=x*y;
  12. 	if(y!=0){
  13. 		*mod=x/y;
  14. 	}
  15. }
  16.  
  17.  
  18. int main(){
  19. 	int x,y;
  20. 	int sum,diff, mul, mod;
  21. 	scanf("%d %d",&x,&y);
  22. 	cal(x,y,&sum,&diff,&mul,&mod);
  23. 	printf("課題１\nx+y=%d\n|x-y|=%d\nx*y=%d\nx/y=%d",sum,diff,mul,mod);
  24. 	return 0;
  25. }
Success #stdin #stdout 0s 5284KB
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課題１
x+y=3
|x-y|=1
x*y=2
x/y=0
https://ideone.com/0O5a7w
language:
C (gcc 8.3)
created:
13 hours ago
visibility:
public

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