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  1. #include <bits/stdc++.h>
  2. using namespace std;
  3. int getCount(int x){
  4. 	int count=0;
  5. 	while(x!=0){
  6. 		x=x/10;
  7. 		count++;
  8.  
  9. 	}
  10. 	return count;
  11. }
  12.  
  13. int main() {
  14. 	// your code goes here
  15. 	int arr[]={10,2};
  16. 	int n=sizeof(arr)/sizeof(arr[0]);
  17. 	int sumArray=0;
  18. 	for(int i=0;i<n;i++){
  19. 		sumArray=sumArray+arr[i];
  20. 	}
  21. 	int digit[10]={0};      //digit array to get count of digit in number 
  22. 	for(int i=0;i<n;i++){
  23. 		int y=getCount(arr[i]);
  24. 		digit[y]=digit[y]+1;
  25. 	}
  26. 	int val=0;
  27. 	int sum=0;
  28. 	for(int i=1;i<n;i++){
  29. 		int j=1;
  30. 		while(j<=6){          //Becuase the contraints has a number containing the digit size of 6
  31. 			val+=arr[i]*pow(10,j)*digit[j]; 
  32. 			j++;                         //while looop used to get all digit size of 1 ,2 .. for the given element at i as we want all possible number for ith element
  33. 		}
  34. 		sum+=val+sumArray;
  35. 	}
  36. 	cout<<"The sum is:"<<sum;
  37. 	return 0;
  38. }
Success #stdin #stdout 0.01s 5328KB
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Standard input is empty
stdout
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The sum is:232
https://ideone.com/09bsnl
language:
C++ (gcc 8.3)
created:
6 days ago
visibility:
public

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