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  1. import re
  2. test_str = "[1]first[2]second[3]third"
  3. print( re.split(r'(?!^)(?=\[\d+\])', test_str) )
Success #stdin #stdout 0.04s 9412KB
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Standard input is empty
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['[1]first', '[2]second', '[3]third']
https://ideone.com/04xsCe
language:
Python 3 (python  3.9.5)
created:
2 years ago
visibility:
public

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