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  1. for terms_cnt in range (1,n+1):
  2.     answer[terms_cnt]=0
  3.     for groups in range (1,terms_cnt+1):
  4.         answer[terms_cnt]+=stirling_number_2nd_kind[terms_cnt][groups]*factorial[groups]
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https://ideone.com/00UUdf
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Text (text 6.10)
created:
7 years ago
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