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  1. meany = ...
  2. @(n)1+sum(fix(log2(1:n-1)))/n
  3.  
  4. meany(1)
  5. meany(2)
  6. meany(3)
  7. meany(4)
  8. meany(5)
  9. meany(6)
  10. meany(7)
  11.  
Success #stdin #stdout 0.45s 121792KB
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meany =

@(n) 1 + sum (fix (log2 (1:n - 1))) / n

ans =  1
ans =  1
ans =  1.3333
ans =  1.5000
ans =  1.8000
ans =  2
ans =  2.1429
https://ideone.com/3i9BsB
language:
Octave (octave 4.4.1)
created:
7 years ago
visibility:
public

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