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  1. #include <chrono>
  2. #include <iostream>
  3. #include <vector>
  4.  
  5. int main(int argc, char**)
  6. {
  7. 	const auto t_0 = std::chrono::high_resolution_clock::now();
  8. 	std::vector<int> v(argc * 1000 * 1000, 0);
  9. 	const auto t_1 = std::chrono::high_resolution_clock::now();
  10. 	std::vector<int*> pv(argc * 1000 * 1000, nullptr);
  11. 	for (  auto& e : pv )
  12. 	{
  13. 		e = new int(0);
  14. 	}
  15. 	const auto t_2 = std::chrono::high_resolution_clock::now();
  16. 	auto rv = [&]()
  17. 	{
  18. 		int sum = 0;
  19. 		for ( const auto& e : v )
  20. 		{
  21. 			sum += e;
  22. 		}
  23. 		return sum;
  24. 	}();
  25. 	const auto t_3 = std::chrono::high_resolution_clock::now();
  26. 	auto rpv = [&]()
  27. 	{
  28. 		int sum = 0;
  29. 		for ( const auto& e : pv )
  30. 		{
  31. 			sum += *e;
  32. 		}
  33. 		return sum;
  34. 	}();
  35. 	const auto t_4 = std::chrono::high_resolution_clock::now();
  36. 	for ( auto& e : pv )
  37. 	{
  38. 		delete e;
  39. 	}
  40. 	const auto t_5 = std::chrono::high_resolution_clock::now();
  41. 	std::cout << (t_1 - t_0).count() << " for construction of v\n"
  42. 	          << (t_3 - t_2).count() << " for sum of v\n"
  43. 	          << (t_3 - t_2).count() + (t_1 - t_0).count() << " in total for v\n"
  44. 	          << (t_2 - t_1).count() << " for construction of pv\n"
  45. 	          << (t_4 - t_3).count() << " for sum of pv\n"
  46. 	          << (t_5 - t_4).count() << " for destruction of pv\n"
  47. 	          << (t_2 - t_1).count() + (t_4 - t_3).count() + (t_5 - t_4).count() << " in total for pv\n";
  48. 	return rpv - rv;
  49. }
Success #stdin #stdout 0.1s 18848KB
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stdin
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Standard input is empty
stdout
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3697674 for construction of v
1385545 for sum of v
5083219 in total for v
64752873 for construction of pv
4700794 for sum of pv
32847649 for destruction of pv
102301316 in total for pv
https://ideone.com/k7CFWK
language:
C++14 (gcc 8.3)
created:
9 years ago
visibility:
public

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