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  1. #include <iostream>
  2. #include <sstream>
  3. #include <string>
  4.  
  5. using namespace std;
  6.  
  7. int main() {
  8.     ostringstream ss;
  9.     ss << scientific << 123456789.87654321;
  10.     string s = ss.str();
  11.     s.replace(s.find("e"), 1, "*10^");
  12.     cout << s << endl;
  13. 	return 0;
  14. }
Success #stdin #stdout 0.01s 2816KB
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stdin
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Standard input is empty
stdout
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1.234568*10^+08
https://ideone.com/TzEvs
language:
C++ (gcc 8.3)
created:
11 years ago
visibility:
public

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