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  1. #include <stdio.h>
  2.  
  3. void test_float() {
  4. 	float d = 0.01f;
  5. 	float n = 0.0f;
  6. 	for (int i = 0 ; i < 100 ; ++i) {
  7. 		n += d;
  8. 	}
  9. 	if (n < 1.0) {
  10. 		printf("float: n (%f) < 1.0\n", n);
  11. 	} else {
  12. 		printf("float: n (%f) >= 1.0\n", n);
  13. 	}
  14. }
  15.  
  16. void test_double() {
  17. 	double d = 0.01;
  18. 	double n = 0.0;
  19. 	for (int i = 0 ; i < 100 ; ++i) {
  20. 		n += d;
  21. 	}
  22. 	if (n < 1.0) {
  23. 		printf("double: n (%f) < 1.0\n", n);
  24. 	} else {
  25. 		printf("double: n (%f) >= 1.0\n", n);
  26. 	}
  27. }
  28.  
  29. int main(void) {
  30. 	test_float();
  31. 	test_double();
  32. 	return 0;
  33. }
  34.  
Success #stdin #stdout 0s 2160KB
comments (?)
stdin
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Standard input is empty
stdout
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float: n (0.999999) < 1.0
double: n (1.000000) >= 1.0
https://ideone.com/HG6j4I
language:
C (gcc 8.3)
created:
8 years ago
visibility:
public

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