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#include <stdio.h>
#include <math.h>
 
double f1(double x)
{
	return 1;
}
 
double f2(double x)
{
	return x;
}
 
double int1_1_0(double x)//f(x)=1
{
	return 0.5;
}
 
double int2_1_0(double x)//f(x)=1
{
	return 1.0/3;
}
 
int main(void)
{
	double C1 = (2-5*sqrt(6)/18);
	double C2 = 5*sqrt(6)/18-1.5;
	double x1 = (6-sqrt(6))/10;
	double x2 = (6+sqrt(6))/10;
	double left = int1_1_0;
	double right = C1*f1(x1)+C2*f2(x2);
	printf("%lf=%lf\n",left, right);
	left = int2_1_0;
	right = C1*f2(x1)+C2*f2(x2);
	printf("%lf=%lf\n",left, right);
	return 0;
}
 

prog.cpp: In function ‘int main()’:
prog.cpp:30:16: error: cannot convert ‘double (*)(double)’ to ‘double’ in initialization
  double left = int1_1_0;
                ^~~~~~~~
prog.cpp:33:9: error: cannot convert ‘double(double)’ to ‘double’ in assignment
  left = int2_1_0;
         ^~~~~~~~

Standard output is empty