language: Python (python 2.7.3)
date: 201 days 20 hours ago
link:
visibility: public 
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# numbers = [1, 15, 7, 3, 8, 8, 19, 5, 12, 8, 2, 6, 8]
numbers = [1, 15, 8, 8, 8, 8, 7, 3, 19, 5, 12, 2, 6]
 
counter = 1
prev = numbers.pop()
 
while len(numbers) > 0 and counter < 4:
    next = numbers.pop()
    if prev == next: 
        counter = counter + 1
    else:
        counter = 1
        prev = next
 
if counter == 4: 
    print "Found repeated number"
else: 
    print "No repeated number found"