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  1. # numbers = [1, 15, 7, 3, 8, 8, 19, 5, 12, 8, 2, 6, 8]
  2. numbers = [1, 15, 8, 8, 8, 8, 7, 3, 19, 5, 12, 2, 6]
  3.  
  4. counter = 1
  5. prev = numbers.pop()
  6.  
  7. while len(numbers) > 0 and counter < 4:
  8.     next = numbers.pop()
  9.     if prev == next: 
  10.         counter = counter + 1
  11.     else:
  12.         counter = 1
  13.         prev = next
  14.  
  15. if counter == 4: 
  16.     print "Found repeated number"
  17. else: 
  18.     print "No repeated number found"
  19.  
  20.  
Success #stdin #stdout 0.08s 10864KB
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stdin
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Standard input is empty
stdout
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Found repeated number
https://ideone.com/2dd6zf
language:
Python (cpython 2.7.16)
created:
11 years ago
visibility:
public

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