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  1. import re
  2.  
  3. s = '#100001000100#'
  4. res = re.findall(r'#((?:10{2,})+)#', s)
  5. print(res)
  6.  
Success #stdin #stdout 0.04s 9848KB
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stdin
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Standard input is empty
stdout
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['100001000100']
https://ideone.com/zRT5dU
language:
Python 3 (python  3.9.5)
created:
5 years ago
visibility:
secret

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