#include <stdio.h>
#include <math.h>
int main()
{
int n=4;
double a[n];
a[0]=0;
a[1]=0;
a[2]=1.5;
for(int i=3;i<n;i++)
{
a
[i
]=((i
+1)/(pow(i
,2)+1))*a
[i
-1]-(a
[i
-2]*a
[i
-3]);}
printf("Твое число : %f\n",a
[n
-1]); return 0;
}
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