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  1. #include<bits/stdc++.h>
  2. using namespace std;
  3. int main()
  4. {
  5.     string id;
  6.     long long int a, c, x, m,p,q,lastNonzero=0,n=10;
  7.     cout<<"Enter your departmental ID: "<<endl;
  8.     getline(cin,id);
  9.  
  10.     for(int i = id.length()-1 ; i >=0; i--)
  11.     {
  12.         if(id[i]>'0' && id[i]<='9')
  13.         {
  14.             lastNonzero++;
  15.             if(lastNonzero==1)
  16.             {
  17.                 a = abs(id[i]-48);
  18.             }
  19.             else if(lastNonzero==2)
  20.             {
  21.                 c = abs(id[i]-48);
  22.             }
  23.             else if(lastNonzero==3)
  24.             {
  25.                 x = abs(id[i]-48);
  26.             }
  27.             else
  28.             {
  29.                 break;
  30.             }
  31.         }
  32.     }
  33.     cout<<"Your Departmental ID : "<<id<<endl;
  34.     cout<<"Here,"<<endl<<"last nonzero (a): "<<a<<endl<<"2nd last nonzero (c): "<<c<<endl<<"3rd last nonzero (x): "<<x<<endl;
  35.     m = 18%c;
  36.     if(m==0){
  37.         m = 5;
  38.     }
  39.     q = c%m;
  40.     cout<<"and the value of m: "<<m<<endl;
  41.     cout<<endl<<"\t\tApplying Linear Congruential Method (x = a*x+c%m) for 10 times"<<endl<<endl;
  42.     for(int i = 1 ; i <= n ; i++){
  43.         p = a*x;
  44.         x = p+q ;
  45.         cout<<"for x"<<i<<" = "<<x<<" (Where a*x: "<<p<<" and c mod m: "<<q<<")"<<endl;
  46.     }
  47. }
  48.  
Success #stdin #stdout 0s 5328KB
comments (?)
stdin
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CSE 01806649
stdout
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Enter your departmental ID: 
Your Departmental ID : CSE 01806649
Here,
last nonzero (a): 9
2nd last nonzero (c): 4
3rd last nonzero (x): 6
and the value of m: 2

		Applying Linear Congruential Method (x = a*x+c%m) for 10 times

for x1 = 54 (Where a*x: 54 and c mod m: 0)
for x2 = 486 (Where a*x: 486 and c mod m: 0)
for x3 = 4374 (Where a*x: 4374 and c mod m: 0)
for x4 = 39366 (Where a*x: 39366 and c mod m: 0)
for x5 = 354294 (Where a*x: 354294 and c mod m: 0)
for x6 = 3188646 (Where a*x: 3188646 and c mod m: 0)
for x7 = 28697814 (Where a*x: 28697814 and c mod m: 0)
for x8 = 258280326 (Where a*x: 258280326 and c mod m: 0)
for x9 = 2324522934 (Where a*x: 2324522934 and c mod m: 0)
for x10 = 20920706406 (Where a*x: 20920706406 and c mod m: 0)
https://ideone.com/wQeNEh
language:
C++ (gcc 8.3)
created:
2 years ago
visibility:
public

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