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  1. char s[99];i;k,l,m;main(j){for(;gets(s);printf("%*s*\n",(int)(i*40/(j-m)-.1),""))for(j=strlen(s),m=k=i=0;k<j;k++,m+=s[k]==32)for(l=0;l<10;l++)i+=s[k]=="AIUEOaiueo"[l];}
Success #stdin #stdout 0.01s 5512KB
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Patzcca
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          *
https://ideone.com/jxFOny
language:
C (gcc 8.3)
created:
1 year ago
visibility:
public

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