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  1. ls = [1,2,3,4,5]
  2. index= 3
  3. print(ls[index:]+ls[:index+3])
  4. print(ls[index+3:]+ls[:len(ls)-index])
  5. print(ls[index:index+3]+ls[:len(ls)-index])
  6. print(ls[index:index+3] + ls[:max(0,-1*(len(ls)-index-3))])
Success #stdin #stdout 0.01s 27712KB
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[4, 5, 1, 2, 3, 4, 5]
[1, 2]
[4, 5, 1, 2]
[4, 5, 1]
https://ideone.com/PwpZRw
language:
Python 3 (python  3.9.5)
created:
5 years ago
visibility:
public

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