import numpy
foo = [1, 2, 3]
bar = [[1, 5, 3], [3, 4, 1], [6, 2, 1]]
print(bar)
print(numpy.array(bar).flatten())
print([[e for e in a if e not in foo] for a in bar])
c = numpy.array([list(e for e in a if e not in foo) for a in bar])
print(c.flatten())
print()
aW1wb3J0IG51bXB5CgoKZm9vID0gWzEsIDIsIDNdCmJhciA9IFtbMSwgNSwgM10sIFszLCA0LCAxXSwgWzYsIDIsIDFdXQoKcHJpbnQoYmFyKQpwcmludChudW1weS5hcnJheShiYXIpLmZsYXR0ZW4oKSkKcHJpbnQoW1tlIGZvciBlIGluIGEgaWYgZSBub3QgaW4gZm9vXSBmb3IgYSBpbiBiYXJdKQpjID0gbnVtcHkuYXJyYXkoW2xpc3QoZSBmb3IgZSBpbiBhIGlmIGUgbm90IGluIGZvbykgZm9yIGEgaW4gYmFyXSkKcHJpbnQoYy5mbGF0dGVuKCkpCnByaW50KCk=
[[1, 5, 3], [3, 4, 1], [6, 2, 1]]
[1 5 3 3 4 1 6 2 1]
[[5], [4], [6]]
[5 4 6]