(* From a list of given numbers, find out which pairs are friends.
A pair of numbers, (A,B), is friend when A+B is a number which last digit is 0. *)
 
program friends_challenge;
uses crt;  // for the Pause method, only
 
type TPair = record
        a, b : byte;
     end;
     TList = array of byte;
     TFrs  = array of TPair;
 
// Pause method (compacted in one line):
procedure Pause; begin repeat until readkey = #13; end;
 
procedure GetNumbers(const q : byte; var list : TList);
(* Gets the list of numbers from the user. *)
var i : byte;
begin
    SetLength(list, q);
    for i:=0 to q-1 do
        readln(list[i]);
end;
 
procedure GetFriends(const list : TList; var frs : TFrs);
(* Algorithm - gets the list of pairs of numbers which are friends. *)
const MAX = 255;
var i, j : byte;
    seen : array [0..MAX, 0..MAX] of boolean;
begin
    // initialization fo "seen"
    for i:=0 to MAX do for j:=0 to MAX do seen[i,j]:=false;
 
    // finding the friends...
    for i:=low(list) to high(list)-1 do
        for j:=i+1 to high(list) do
            if ((list[i] + list[j]) mod 10 = 0) and not seen[list[i], list[j]] then begin
                SetLength(frs, Length(frs)+1);
                frs[Length(frs)-1].a := list[i];
                frs[Length(frs)-1].b := list[j];
                seen[list[i], list[j]] := true;
                seen[list[j], list[i]] := true;
            end;
end;
 
var n : byte;         // how many numbers will be given
    numbers : TList;  // the list of numbers to search
    friends : TFrs;   // the list of pairs of number which are friends
    elem : TPair;     // usage: FOR-IN cycle
 
begin
    // INPUT
    repeat
        readln(n);
        if (n < 2) then writeln('Must be greater than or equal to 2!');
    until (n >= 2);
 
    GetNumbers(n, numbers);        // getting the list...
    GetFriends(numbers, friends);  // getting the friends...
 
    // OUTPUT
    write('The ', Length(friends), ' friend pairs are: ');
    for elem in friends do write('(', elem.a, ',', elem.b, ') ');
    Pause;
end.