#include <iostream>
#include <cstdlib>
div_t
divide (int numer, int denom)
{
    div_t result;
	result.quot = numer / denom;
	result.rem = numer % denom;
	/* The ANSI standard says that |QUOT| <= |NUMER / DENOM|, where
	   NUMER / DENOM is to be computed in infinite precision.  In
	   other words, we should always truncate the quotient towards
	   zero, never -infinity.  Machine division and remainer may
	   work either way when one or both of NUMER or DENOM is
	   negative.  If only one is negative and QUOT has been
	   truncated towards -infinity, REM will have the same sign as
	   DENOM and the opposite sign of NUMER; if both are negative
	   and QUOT has been truncated towards -infinity, REM will be
	   positive (will have the opposite sign of NUMER).  These are
	   considered `wrong'.  If both are NUM and DENOM are positive,
	   RESULT will always be positive.  This all boils down to: if
	   NUMER >= 0, but REM < 0, we got the wrong answer.  In that
	   case, to get the right answer, add 1 to QUOT and subtract
	   DENOM from REM.  */
	if (numer >= 0 && result.rem < 0)
		{
			++result.quot;
			result.rem -= denom;
		}
	return result;
}

int main()
{
	int num = -42, div = 5;
	std::div_t res = divide(num, div);
	std::cout << "Result: " << res.quot << ":" << res.rem << std::endl;

}