import math


def find(n):
    # max of x can be sqrt of n
    n1 = int(math.ceil(math.sqrt(n)))
    lst = []

    for i in range(1, n1):
        for j in range(i + 1, n1):

            if i**2 + j**2 >= n:
                break

            tz = int(math.sqrt(n - i**2 - j**2))
            if tz ** 2 == n - i**2 - j**2:
                a = [i, j, tz]
                lst.append(a)
    return lst

print find(12345678)