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  1.  #include <stdio.h>
  2. int main(void) {
  3.  int i,j;
  4.  float f,g;
  5.  
  6.  i = 5; j = 2;
  7.  f = 3.0;
  8.  f = f + j / i;
  9.  printf("value of f is:%f \n",f);
  10.  g = (f + j )/i;
  11.  printf("value of g is:%f \n",g);
  12.  return 0;
  13. }
Success #stdin #stdout 0s 10320KB
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stdin
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Standard input is empty
stdout
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value of f is:3.000000 
value of g is:1.000000
https://ideone.com/nPsPB5
language:
C (gcc 8.3)
created:
6 years ago
visibility:
public

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