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  1. #arrの中から連続するnumの回数を配列にして返す
  2. def repeat_times(arr,num):
  3.   res = []
  4.   rp = 0
  5.   for i in range(len(arr)):
  6.     if arr[i] != num:
  7.       if rp > 0:
  8.         res.append(rp)
  9.         rp = 0
  10.     else:
  11.       rp += 1
  12.   if rp > 0:
  13.     res.append(rp)
  14.   return res
  15.  
  16. a = [0,1,1,1,0,0,0,0,1,1,0,1,1,1,1,1,0,1,0]
  17. ans = repeat_times(a,1)
  18. print(ans)
  19. ans = repeat_times(a,0)
  20. print(ans)
  21.  
Success #stdin #stdout 0.03s 9196KB
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Standard input is empty
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[3, 2, 5, 1]
[1, 4, 1, 1, 1]
https://ideone.com/mzCrUK
language:
Python 3 nbc (python 3.7.3)
created:
1 year ago
visibility:
secret

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