• Source 
    1. def contacodon(seq):
    2.     # Lista de stop codons:
    3.     stops = ["TAA", "TAG", "TGA"]
    4.  
    5.     count = {}
    6.     for i in range(seq.find('ATG'), len(seq) + 1, 3):
    7.         codon = seq[i: i + 3]
    8.         if codon in count:
    9.             count[codon] += 1
    10.         else:
    11.             count[codon] = 1
    12.  
    13.         # Se tiver encontrado um stop codon, pare de iterar:
    14.         if codon in stops:
    15.             break
    16.     return count
    17.  
    18.  
    19. seq = "GCGATCGAGATGAGCATCGCATCGCGGACTACCGCGCGCGCGCGCGGGAGATGAGCATCGACGACTCGACTAG"
    20. print(contacodon(seq))
    21.