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#include <stdio.h>
 
int main(void) {
	int array[]={0,1,2,3,4,5,6};
	int head, tail, key = 0,6,5;
	int center;
 
	for(;;){
		if(head<=tail)
			center=(head+tail)/2;
		else
			printf("ilchi X")
			break;
		if(array[center]==key)
			printf("key=%d",center);
			break;
		else if(array[center]<key)
			head=center+1
		else
			tail=center-1
	}
}
 

prog.c: In function ‘main’:
prog.c:5:26: error: expected identifier or ‘(’ before numeric constant
  int head, tail, key = 0,6,5;
                          ^
prog.c:13:4: error: expected ‘;’ before ‘break’
    break;
    ^~~~~
prog.c:14:3: warning: this ‘if’ clause does not guard... [-Wmisleading-indentation]
   if(array[center]==key)
   ^~
prog.c:16:4: note: ...this statement, but the latter is misleadingly indented as if it is guarded by the ‘if’
    break;
    ^~~~~
prog.c:17:3: error: ‘else’ without a previous ‘if’
   else if(array[center]<key)
   ^~~~
prog.c:19:3: error: expected ‘;’ before ‘else’
   else
   ^~~~

Standard output is empty