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  1. //a JAVA program to find if the number to be searched is present in the array
  2. import java.util.*;
  3. class search_array
  4. {
  5. 	public static void main (String[] args) throws java.lang.Exception
  6. 	{
  7. 		Scanner sc=new Scanner(System.in);
  8. 		int arr[]=new int[10];
  9.  
  10. 		for(int i=0;i<10;i++)
  11. 		{
  12. 			arr[i]=sc.nextInt();
  13.  
  14. 		}
  15. 		System.out.println("Array of 10 element entered by user is:");
  16. 		for(int i=0;i<10;i++)
  17. 		{
  18. 			System.out.println(arr[i]);
  19. 		}
  20.  
  21. 		int p=0,n=0,ev=0,od=0;
  22. 		for(int i=0;i<10;i++)
  23. 		{
  24. 			if(arr[i]<0)
  25. 			n++;
  26.  
  27. 			if(arr[i]>0)
  28. 			p++;
  29.  
  30. 			if(arr[i]%2==0)
  31. 			ev++;
  32.  
  33. 			if(arr[i]%2!=0)
  34. 			od++;
  35.  
  36.  
  37. 		}
  38.  
  39. 		System.out.println("number of positive numbers are:"+p);
  40. 		System.out.println("number of negative numbers are:"+n);
  41. 		System.out.println("number of even numbers are:"+ev);
  42. 		System.out.println("number of odd numbers are:"+od);
  43.  
  44.  
  45.  
  46.  
  47. 	}
  48. }
Success #stdin #stdout 0.13s 35968KB
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stdin
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4  5  2  6  1  -1  7  9  -3  3
stdout
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Array of 10 element entered by user is:
4
5
2
6
1
-1
7
9
-3
3
number of positive numbers are:8
number of negative numbers are:2
number of even numbers are:3
number of odd numbers are:7
https://ideone.com/Xht6Jj
language:
Java (HotSpot 12)
created:
126 days ago
visibility:
public

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