#include<iostream>
#include<string>
using namespace std;
int notation(string str1,string str2,int N)
{
	int e=0;//定义e作为返回结果
	int pos =0;//用来记录下标无用的0最后出现的位置
	//除去前面无用的0
	for(int i=0;i<(int(str1.length())-1);i++)//长度减一是为了防止出现全是0的情况
	{
		if(str1[i]=='0'&&str1[i+1]!='.')
			pos++;
	}
	str1.erase(str1.begin(),str1.begin()+pos);
 
	int n=0;//记录已被记录的数的个数
	int i=0;//用来记录下标所到位置
	//如果除去无用0后开头不是0时，就开始记录前面N个数，让e等于小数点前数字的个数
	if(str1[0]!=0)
	{
		while(i<int(str1.length())&&n<N)
		{
			if(str1[i]!='.')
				str2[n++]=str1[i];
			i++;
		}
		i=0;
		while(str1[i]!='.'&&i<int(str1.length()))
			e++;
	}
	//如果除去无用0后开头为0
	else
	{
		//记录所前面N个不为0的数
		while(i<int(str1.length())&&n<N)
		{
			if(str1[i]!='0'&&str1[i]!='.')
				str2[n++]=str1[i];
		}
		//如果记录后长度还是为0，就让计数为0，e为0
		if(n==0)
		{
			for(n=0;n<N;n++)
				str2[n]='0';
		}
		//否则让e为小数点后0的个数
		else
		{
			int j=0;
			while(str1[j]==0)
				j++;
			e=-(j-2);
		}
	}
	return e;
}	
//输出处理
void show(string  str,int N,int e)
{
	if(int(str.length())==N)
	{
		cout<<"0."<<str<<"*10^"<<e<<endl;
	}
	else
	{
		cout<<"0."<<str;
		for(int i=0;i<(N-int(str.length()));i++)
			cout<<"0";
		cout<<"*10^"<<e<<endl;
	}
}	
int main()
{
	int N;
	string str1,str2;
	cin>>N>>str1>>str2;
	string str3,str4;
	//生产科学计数，以及e
	int e1=notation(str1,str3,N);
	int e2=notation(str2,str4,N);
	//比较大小并进行输出
	if(e1!=e2||str3!=str4)
	{
		cout<<"no";
		show(str3,N,e1);
		show(str4,N,e2);
	}
	else
	{
		cout<<"no";
		show(str4,N,e2);
	}
}	

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