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  1. #include <iostream>
  2. #include <cmath>
  3. using namespace std;
  4. int main()
  5. {
  6.  float q, t, r, u, x, x1, x2,n1,e1;
  7.  float p1 = 981,g = 9.80,l = 2.00e-3,b = 8.23e-3,p = 0.101e6,d = 5.00e-3,n = 1.83e-5;
  8.  cout<<"先输入时间,再输入电压:"<<endl;
  9.  cin >> t>>u;
  10.  r = sqrt(9 * n*l / (2 * p1*g*t));
  11.  x1 = ((n*l) / (t*(1 + b / (p*r))));
  12.  x2 = x1*x1*x1;
  13.  x = sqrt(x2);
  14.  q = 18 * 3.14*x*d / (sqrt(2 * p1*g)*u);
  15.  n1=q/(1.6e-19);
  16.  if(n1-int(n1)>=0.5)
  17.     {
  18.         n1=int(n1)+1;
  19.     }
  20.     else if(n1-int(n1)<0.5||n1-int(n1)>=0)
  21.     {
  22.         n1=int(n1);
  23.     }
  24.     else
  25.     {
  26.         cout<<"error";
  27.     }
  28.     e1=q/n1;
  29.  cout << "半径r=   "<<r <<endl;
  30.  cout<<"电量q=   "<< q<<endl;
  31.  cout<<"油滴所带基本电荷n=   "<<n1<<endl;
  32.  cout<<"实验数据所得电荷量e=   "<<e1;
  33.  return 0;
  34. }
Success #stdin #stdout 0.01s 5464KB
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stdin
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stdout
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先输入时间,再输入电压:
半径r=   8.66066e-07
电量q=   4.75991e-19
油滴所带基本电荷n=   3
实验数据所得电荷量e=   1.58664e-19
https://ideone.com/SEZsJ1
language:
C++14 (gcc 8.3)
created:
1 year ago
visibility:
public

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