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  1. #include <stdio.h>
  2.  
  3. r,m;f(char*s){for(r=m=0;*s;r-=*s++==93)r+=*s==91,m=r>m?r:m;return m;}
  4.  
  5. int main(void) {
  6. 	char string[1000], i;
  7. 	for(i=0; i<8; i++){
  8. 		gets(string);
  9. 		printf("%i\n", f(string));
  10. 	}
  11. 	return 0;
  12. }
Success #stdin #stdout 0s 2116KB
comments (?)
stdin
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[1]
[1, 2, 3]
[[1, 2, 3]]
[3, [3, [3], 3], 3]
[[[[1], 2], [3, [4]]]]
[1, [[3]], [5, 6], [[[[8]]]], 1]
[1, [[2, 3, [[4], 5], 6, [7, 8]], 9, [10, [[[11]]]], 12, 13], 14]
[[[[[[[3]]]]]]]
stdout
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https://ideone.com/IC23Bc
language:
C (gcc 8.3)
created:
8 years ago
visibility:
public

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