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  1. /*
  2. Template belongs to : Himanshu Jaju [himanshujaju]
  3. */
  4.  
  5. #include<bits/stdc++.h>
  6. using namespace std;
  7.  
  8. typedef long long int LL;
  9.  
  10. #define inp_s     ios_base::sync_with_stdio(false)
  11. #define DRT()     int test_case;cin>>test_case;while(test_case--)
  12.  
  13. #define VI        vector<int>
  14. #define VS        vector<string>
  15. #define VLL       vector<LL>
  16. #define PII       pair<int,int>
  17. #define all(c)    c.begin(),c.end()
  18. #define sz(c)     c.size()
  19. #define clr(c)    c.clear()
  20. #define msi       map<string,int>
  21. #define msit      map<string,int>::iterator
  22. #define pb        push_back
  23. #define mp        make_pair
  24.  
  25. #define GI(x)     scanf("%d",&x);
  26. #define GLL(x)    scanf("%lld",&x);
  27. #define GSTR(x)   scanf("%s",x);
  28.  
  29. #define PI(x)     printf("%d",x);
  30. #define PLL(x)    printf("%lld",x);
  31. #define PSTR(x)   printf("%s",x);;
  32.  
  33. #define FOR(i,a,b)      for(int i=a;i<b;i++)
  34. #define RFOR(i,a,b)     for(int i=b-1;i>=a;i--)
  35.  
  36. #define gcd(a,b)  __gcd(a,b)
  37. #define MOD       1000000007
  38.  
  39. #define STEPS     1000
  40. #define CHARACTER 26
  41.  
  42. int main()
  43. {
  44.       DRT()
  45.       {
  46.             int n;
  47.             LL k;
  48.             cin>>n>>k;
  49.             if(k>STEPS) k = STEPS;
  50.             string str;
  51.             cin>>str;
  52.             double mat[26][26] = {0};
  53.             FOR(i,0,26) FOR(j,0,26) cin>>mat[i][j];
  54.  
  55.             double dp[3][STEPS+1][CHARACTER] = {0};
  56.             FOR(i,0,sz(str)) dp[i][0][str[i]-'a']++;
  57.  
  58.  
  59.             FOR(x,0,sz(str)) FOR(i,0,STEPS) FOR(j,0,26) FOR(k,0,26) dp[x][i+1][k] += dp[x][i][j]*mat[j][k];
  60.  
  61.             double ans = 0;
  62.             set<string> kkkk;
  63.             while(n--)
  64.             {
  65.                   string s;
  66.                   cin>>s;
  67.                   if(kkkk.find(s)!=kkkk.end() || sz(s) != sz(str)) continue;
  68.                   kkkk.insert(s);
  69.                   double x = 1;
  70.                   FOR(i,0,sz(s)) x = (x*dp[i][k][s[i]-'a']);
  71.                   ans += x;
  72.             }
  73.             printf("%.10lf\n",ans);
  74.       }
  75.       return 0;
  76. }
Success #stdin #stdout 0.01s 3972KB
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stdout
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0.1250000006
0.1250000006
https://ideone.com/AV9g0U
language:
C++ (gcc 8.3)
created:
9 years ago
visibility:
secret

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