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  1. def F(n):
  2. 	if n<5:
  3. 		return 5-n
  4. 	elif n >=5 and (n%3 == 0):
  5. 		return 4*(n-5)*F(n-5)
  6. 	else:
  7. 		return 3*n + 2*F(n-1) + F(n-2)
  8. n=20
  9. print(F(n))
Success #stdin #stdout 0.03s 9212KB
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1343116
https://ideone.com/8G8a9P
language:
Python 3 (python  3.9.5)
created:
3 years ago
visibility:
public

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